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![SOLVED: (a) Show the commutator of a product of operators A, B, and C satisfies [A, BC] = [A, B]C + B[A, C]. (b) Ehrenfest's theorem is a relationship between the expectation](https://cdn.numerade.com/ask_images/fc46b9bd917a45deb5443d7e814fe9d9.jpg "SOLVED: (a) Show the commutator of a product of operators A, B, and C satisfies [A, BC] = [A, B]C + B[A, C]. (b) Ehrenfest's theorem is a relationship between the expectation")
SOLVED: (a) Show the commutator of a product of operators A, B, and C satisfies [A, BC] = [A, B]C + B[A, C]. (b) Ehrenfest's theorem is a relationship between the expectation
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![SOLVED: Question 15 (10 marks): Let G be a group. A commutator in G is the product [a, b] = aba^(-1)b^(-1) where a, b ∈ G. Show that ab = ba if](https://cdn.numerade.com/ask_images/b36222bceb26487a914cf256ef7740f2.jpg "SOLVED: Question 15 (10 marks): Let G be a group. A commutator in G is the product [a, b] = aba^(-1)b^(-1) where a, b ∈ G. Show that ab = ba if")
SOLVED: Question 15 (10 marks): Let G be a group. A commutator in G is the product [a, b] = aba^(-1)b^(-1) where a, b ∈ G. Show that ab = ba if
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![PDF] Commutator width in the first Grigorchuk group | Semantic Scholar](https://d3i71xaburhd42.cloudfront.net/ce073654b395cd1f348505f974984c4e82bd9e90/17-Figure1-1.png "PDF] Commutator width in the first Grigorchuk group | Semantic Scholar")
PDF] Commutator width in the first Grigorchuk group | Semantic Scholar
